# nilpotent matrix index

It does not mean that A^m=0 for every integer. Hi, I have the following matrix and I have to find it's nilpotent index... 0 0 0 0 0. (b) Nilpotent Matrix: A nilpotent matrix is said to be nilpotent of index p, (p â N), i f A p = O, A p â 1 â O, \left( p\in N \right),\;\; if \;\;{{A}^{p}}=O,\,\,{{A}^{p-1}}\ne O, (p â N), i f A p = O, A p â 1 = O, i.e. I = I. Deï¬nition 2. Recall that the Core-Nilpotent Decomposition of a singular matrix Aof index kproduces a block diagonal matrix â C 0 0 L ¸ similar to Ain which Cis non-singular, rank(C)=rank ¡ Ak ¢,and Lis nilpotent of index k.Isitpossible 0 0 8 0 0. if p is the least positive integer for which A p = O, then A is said to be nilpotent of index p. (c) Periodic Matrix: In general, sum and product of two nilpotent matrices are not necessarily nilpotent. nilpotent matrix The square matrix A is said to be nilpotent if A n = A â¢ A â¢ â¯ â¢ A â n times = ð for some positive integer n (here ð denotes the matrix where every entry is 0). Say B^n = 0 where n is the smallest positive integer for which this is true. But then 0 = CB^n = B^(n-1), a contradiction. Now suppose it were invertible and let C be it's inverse. I've tried various things like assigning the matrix to variable A then do a solve(A^X = 0) but I only get "warning solutions may have been lost" For example, every [math]2 \times 2[/math] nilpotent matrix squares to zero. 0 0 0 3 0. The index of an [math]n \times n[/math] nilpotent matrix is always less than or equal to [math]n[/math]. This definition can be applied in particular to square matrices.The matrix = is nilpotent because A 3 = 0. Consequently, a nilpotent matrix cannot be invertible. the index of the matrix (i.e., the smallest power after which null spaces stop growing). We highly recommend revising the lecture on the minimal polynomial while having the previous proposition in mind. of A.The oï¬-diagonal entries of Tseem unpredictable and out of control. Examples. This means that there is an index k such that Bk = O. But if the two nilpotent matrices commute, then their sum and product are nilpotent as well. A nilpotent matrix cannot have an inverse. If, you still have problem in understanding then please feel free to write back. Products of Nilpotent Matrices Pei Yuan Wu* Department of Applied Mathematics National Chiao Tung University Hsinchu, Taiwan, Republic of China Submitted by Thomas J. Laffey ABSTRACT We show that any complex singular square matrix T is a product of two nilpotent matrices A and B with rank A = rank B = rank T except when T is a 2 X 2 nilpotent matrix of rank one. An n×n matrix B is called nilpotent if there exists a power of the matrix B which is equal to the zero matrix. See nilpotent matrix for more.. By Nilpotent matrix, we mean any matrix A such that A^m = 0 where m can be any specific integer. Theorem (Characterization of nilpotent matrices). The matrix A would still be called Nilpotent Matrix. Then CB = I. A^m=0 may be true for just m=3 but not for m=1 or m=2. In the factor ring Z/9Z, the equivalence class of 3 is nilpotent because 3 2 is congruent to 0 modulo 9.; Assume that two elements a, b in a ring R satisfy ab = 0.Then the element c = ba is nilpotent as c 2 = (ba) 2 = b(ab)a = 0. As to your original problem, you know B^n = 0 for some n. The concept of a nilpotent matrix can be generalized to that of a nilpotent operator. The determinant and trace of a nilpotent matrix are always zero. 6 0 0 0 0. Nilpotent operator. 0 2 0 0 0. An index k such that A^m = 0 for some n. I = I. Deï¬nition 2 equal to the matrix! To your original problem, you know B^n = 0 where m can be generalized to that a. Your original problem, you still have problem in understanding then please feel free to write back =... Be true for just m=3 but not for m=1 or m=2 it does not mean that A^m=0 for every.. As well B^n = 0 where m can be applied in particular to matrices.The... 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